Find the volume of the triangular pyramid to the nearest whole number.
a) 340 in3
b) 567 in3
c) 850 in3
d) 1,133 in3

V = 1/3AH...where A is the the area of triangle base and H is height

lets do area of basearea of triangle is (HB)/2...so the area of the base is
(10* 17) / 2 = 170/2 = 85so in the main formula, A = 85

V = 1/3AHA = 85 and H = 20
V = 1/3(85 * 20)
V = 1/3(1700)
V = 1700/3
V = 566.6 rounds to 567 in^3 <==