Find an equation for the plane that is perpendicular to v = (1, 1, 1) and passes through (1, 0, 0).

The perpendicular vector delivers you the coefficients of the x,y,z variables, so you know that your plane will have the equaction x+y+z = c.

Now all you have to do is find c to make the plane pass through (1,0,0).

If you fill in this point, you get c=1, so the equation is:

x+y+z=1.

Answer: d. 48 step-by-step explanation: i used a calculator so i am 100% sure these are right   mark as brainliest?

Look, when you want to do something like put it like x^2. x2 could mean x² or x₂. so to clear confusion, know the notation. to find the product multiply the x's and you get -8x and the y's and you get 6y. since it's all being multiplied it is just -8x6y, or answer a. although the better answer is -48xy(combining -8 and 6) because you should multiply constants whenever you can.