Dakota knows that ej←→⊥cn←→ and cn←→∥kt←→ .
what other facts can dakota conclude are true?
select each correct answer.
ev←→⊥kt←→
m∠cjv=90°
lk←→∥qt←→
ev←→∥qt←→
two horizontal lines intersecting three vertical lines. the top horizontal line has points c, j, n on it in that order from left to right. the bottom horizontal line has points k, v, t in order from left to right. the first vertical line has points l, c, k in order from top to bottom. the middle vertical line has points e, j, v in order from top to bottom. the last vertical line has q, n, t in order from top to bottom. angle e j v is a right angle.

Given that line EJ is perpendicular to line CN and line CN is parallel to line KT.

Since E, J and V is collinear (are on the same straight line), thus EV is perpendicular to CN, and since CN is parallel to KT, thus EV is perpendicular to KT.

Since line C, J and N are collinear and CN is perpendicular to EJ, this means that line CN and line EJ meets at point J and since they are perpendicular, <CJV = 90 degrees.

Therefore, the correct answers are:

EV←→⊥KT←→
and
m∠CJV=90°

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12