Answer for when sam goes to a restaurant, he always tips the server $2 plus 10% of the cost of the meal. if sam's distribution of meal costs has a mean of $9 and a standard deviation of $3, what are the mean and standard deviation of the distribution of his tips

Given that Sam's distribution of meal costs has a mean of $9 and a standard deviation of $3, this means that the range of Sam's meal cost that are within one standard deviation is given by ($9 - 3, $9 + 3) = ($6, $12).

Given that Sam always tips the server $2 plus 10% of the cost of the meal, this means that when the cost of the meal is $9, Sam tips $2 + (0.1 x 9) = $2 + $0.9 = $2.90

Therefore, the mean of the distribution of Sam's tips is $2.90

Similarly, the range of Sam's tips that are within one standard deviation is given by ($2 + 0.1(6), $2 + 0.1(12)) = ($2 + 0.6, $2 + 1.2) = ($2.6, 3.2) = ($2.9 - $0.3, $2.9 + $0.3)

Therefore, the standard deviation of the distribution of Sam's tips is $0.3

What is the number for e if you don't knkw then there is no answer you need that number to plug in then multiply that number with 5.9 then add 10

With out knowing the functions you have to chose form, this could be one.y = 5.00xx = hours worked and y = the money he will earn.