Two travellers are 220 kilometers apart at noon and are headed toward each other along a straight road. they meet at 5.30 pm and one travelled 20 kilometers per hour faster than the other. what is the speed of the faster traveller?

To solve this, I first draw a picture to visualize. I have a straight line with a point in the middle. The left side of the line represents the distance that one person (A) went. The right side represents the distance that the other person (B) traveled. Let's assume A is the faster traveler and calculate how much extra distance he covered. It took A & B 5.5 hours to meet. 20 km/hr for 5.5 hours is 110 km. So person A not only covered the same distance as B, but also an additional 110 km. To find out how far person B walked, use the following equation: A + B = 220. We now know that A = 110 + B, so I rewrite my equation: (110 + B) + B = 220. Simplify and solve for B: 110 + 2B = 220. Then, 2B = 11-. Finally, B = 55. In 5.5 hours, person B traveled 55 km; therefore, person A traveled 165 km. Finally, divide 165 km by 5.5 hrs, and we find that person A (the faster traveler) traveled at 30 km/hr.