Frederick is working on a number puzzle and discovers that the product of the two base numbers is exactly twice as large as the sum of those same base numbers.
on this, ?

To solve this problem, we are going to use trial and error.
If the 2 numbers are 3 and 4 then 3 and 4 is 12 and 3 + 4 = 7 which cannot be divided equally, so this is not the answer.
3 and 5 = 15 but this is not divisible by 2.
6 and 3 = 18 and 6 + 3 = 9 which is 1/2 of 18
therefore, one set is 6 and 3.