8x^2+23=823

whats going to be the answer i got 0 am i right?

1) No; you are incorrect.  "0" is NOT a solution.

Plug in "0" for "x" ;

8*0² + 23 =? 823? ; 

8*0  + 23 =? 823? ;

  0 + 23 = ? 823 ? ;  No! ;  "0 + 23 = 23 " ; NOT "823" .

2)  The answers:  x = 10, -10 ; or, write as:  x = ± 10 .


To solve:

GIven:  8x² + 23 = 823 ; 

Subtract "23" from EACH SIDE of the equation:

           8x² + 23 - 23 = 823 - 23 ; 
to get:  
           8x²  = 800 ; 

Now, divide EACH SIDE of the equation by "8" ; 

          8x² / 8 = 800 / 8 ;

to get:  x² = 100 ; 

        Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ; 

          √(x²) = √(100) ;

             x  = ± 10 .

The answers:  x = 10, -10 ; or, write as:  x = ± 10 .

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .