The perimeter of a rectangle is 32 feet. the length is 6 more than the width. what are the dimensions of the table?

P=2(L+W)
32=P
32=2(L+W)
divide by 2 both sides
16=L+W

length is 6 more than width
L=6+W
subsisute 6+W for length in other equation

16=L+W
16=6+W+W
16=6+2W
minsu 6 both sides
10=2W
divide both sides by 2
5=W

sub back

L=6+W
L=6+5
L=11

the length is 11ft
the width is 5ft

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