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Asequence is defined recursively using the formula f(n + 1) =f(n) - 5. which sequence could be
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20 solve 2(4 x + 3) < 5 x + 21. a) { x | x < 9} b) { x | x > -5} c) { x | x > -9} d) { x | x < 5}
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Minus 2 open bracket 4g - 3 closed bracket equals 30...
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