Evaluate 5a^2 + 2b^3 when a=4 and b =-4

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5a^2 + 2b^3, solve when a = 4 and b = -4

To solve for this, we must replace "a" with 4, and "b" with -4.

I will set it up;

5(4^2) + 2(-4^3)

Simplify the parenthesis (PEMDAS).

5(16) + 2(-64)

Remove the parenthesis by multiplying them by the numbers to the outside of them.

5 x 16 = 80
2 x -64 = -128

We are now left with:
80 - 128

Simplify.

-48 is your final answer.

I hope this helps!

The length is 23 and y because you add them together