Joe gave the following argument: since lim xβ0 0 = 0,
(a) and since 0 = β1 x + 1 x ,
...
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Mathematics, 05.10.2019 14:00 tcarston1728
Joe gave the following argument: since lim xβ0 0 = 0,
(a) and since 0 = β1 x + 1 x ,
(b) we know that lim xβ0 ( β1 x + 1 x ) = 0.
(c) but then, since lim xβ0 ( β1 x + 1 x ) = lim xβ0 ( β1 x ) + lim xβ0 ( 1 x ),
(d) we can say that lim xβ0 ( β1 x ) + lim xβ0 ( 1 x ) = 0, which means that lim xβ0 ( β1 x ) = β lim xβ0 ( 1 x ).
(e) no error
in which line, if any, has joe made an error?
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Answers: 1
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