12 people are standing in line to buy movie tickets. the theater is running a promotion by giving away 2 concession stand gift cards to the people standing in line.

what is the probability that the 2nd and 3rd people in line will get chosen for the gift cards?

1 in 12 chance of second person getting given a ticket
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct