Find angle abc if the line bd bisects angle abc and given angle abd=5x and angle dbc=3x +10

Angle ABC= Angle B.
He tells you BD bisects angle ABC (B) which means a line passes through the point and splits it into two equal angles= ABD and DBC.
Since ABD=DBC then: 5x=3x+10 
5x-3x=10      2x=10      x=10/2 x=5Since Angle BD bisects angle ABC then Angle ABC equals the two halves ABD and DBC.    substitute x.  ABD=5x=5*5=25  DBC=3x+10=3*5+10=15+10=25  . So ABC = ABD +DBC = 25+25 = 50