Aball is thrown into the air with an upward velocity of 36 ft/s. its height h in feet after t seconds is given by the function h = −16t2 + 36t + 9. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ball’s maximum height?

a. 1.13 s; 69.75 ft

b.1.13 s; 29.25 ft

c.2.25 s; 9 ft

d.1.13 s; 31.5 ft

 B) 1.13 s; 29.25 ft

Step-by-step explanation:

Height of the ball h in feet after t seconds is given by the function

Now at maximum height

=>

After rounding to nearest hundredth,

Height ,

Therefore , t=1.13 s and  

Thus correct option is B) 1.13 s; 29.25 ft

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

14

step-by-step explanation:

14 x 3 = 42