Find the vertex of this parabola y=-x^2+6-8

Hello,

Your equation has a mistake: it is y=-x²+6x-8.

y=-x²+6x-8
 =-(x²-6x)-8
 =-(x²-6x+9-9)-8
 =-(x-3)²+9-8
 =-(x-3)²+1

Vertex is (3,1)

An other way more speedy:
y=-x²+6x-8
y'=-2x+6 =0==>x=3 and y=-3²+6*3-8=1

It meand 4 ytjings so with that thatameksbitnhoe eve rnuch it is

Answercounterclockwise rotation about the origin by 180 degrees followed by reflection about the y-axisexplanationthe given figure has verticesrecall that for counterclockwise rotation about the origin, when we rotate figure pqrs counterclockwise through an angle of 180° about the origin, the coordinates will becomenext, we reflect in the y-axis by negating the x-coordinates of the resulting figure to obtain,therefore the correct answer is c