The quotient of two numbers is 21, their difference is 60 what are the two numbers. and can you explain how you get the answer?

The quotient is the result when you divide two numbers,

i.e. When 6÷3=2 , in this case 2 is the quotient.

The difference is when one number is subtracted from another,

i.e. When 6-1=5 , in this case 5 is the difference.

 So let's call the two numbers you want to find 'x' and 'y'

 So,   

  = 21      and          x - y = 60

 Now we can rearrange these equations to find the values of x and y.

x - y = 60

x = 60 + y

60 + y = 21y

20y = 60

--- y = 3

--- x = 63

answer: i'm great at algebra

~coco

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!