Find the x-intercept and y-intercept of the line. 8x-7y=12

The x-intercept represents the point at which the line hits the x-axis or when the y-value is equal to 0. Similarly, the y-intercept represents the point at which the line hits the y-axis or when the x-value is equal to 0. 

To find the x-intercept, we therefore need to plug in 0 for y and see what we are left with: 8x-7(0)=12 or 8x=12. Then you need to divide both sides by 8 to get x=12/8 or x=3/2. Since we know the y-value is 0 at this point, the x-intercept would be (3/2, 0). Similarly, to find the y-intercept, we need to plug in 0 for x and see what we are left with: 8(0)-7y=12 or -7y=12. Then, you need to divide both sides by -7 to get y=-12/7. Since we know the x-value at this point is 0, the y-intercept would be (0,-12/7).

I hope this helps.