Given a circle with endpoints of a diameter at –10 – 1i and 6 + 11i, answer the questions below. 1. the center of the circle is

The given endpoints which are in imaginary number can be written in Cartesian coordinates form as:

–10 – 1 i = (- 10, - 1)

6 + 11 i = (6, 11)

Since we know that these are the endpoints of the diameter, then this must mean that the center of the circle is the point located in the middle of the endpoints. So we use the middle distance formula to calculate for the coordinates of the center:

x = (-10 + 6) / 2 = - 4 / 2 = -2

y = (- 1 + 11) / 2 = 10 / 2 = 5

So the center is located at:

(- 2, 5)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square