Given the geometric sequence where a1 = 3 and the common ratio is −1, what is the domain for n?

all integers where ≤ 0
all integers where n ≥ 0
all integers where n ≤ 1
all integers where n ≥ 1

someone me. you.

The domain for n is:

All integers where n ≥ 1

Step-by-step explanation:

We are given a geometric sequence where the first term of the sequence is:

and the common ratio(r) is −1.

We are asked to find the domain for n.

We know that the domain of the geometric sequence whose terms are given by are all the natural numbers since by putting the n we get the corresponding term.

Hence, the domain is:

All integers where n ≥ 1

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225