![\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})](/tpl/images/0314/6386/860db.png)
![\\\\\text{Taking cube on both sides, we get}\\\\\Rightarrow(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\\Rightarrow162x^cy^5=(3x^2y)^3(\sqrt[3]{6y^d})^3\\\\\Rightarrow162x^cy^5=27x^{2\times3}y^3(6y^d)......[(a^m)^n=a^{mn}]\\\\\Rightarrow162x^cy^5=162x^6y^{3+d}.........[a^{m}\times\ a^n=a^{m+n}]\\\\\text{Compare the power of corresponding variables, we get}\\\\\Rightarrow\ c=6\ ;\ 3+d=5\Rightarrow\ d=5-3=2](/tpl/images/0314/6386/5593e.png)
What values of c and d make the equation true? 3√162x^cy^5=3x^2y(√6y^d)
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Mathematics, 13.10.2019 02:01 loraine8401
What values of c and d make the equation true? 3√162x^cy^5=3x^2y(√6y^d)
Answers: 2
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