Separate 846 into 3 parts so that the second part is twice the first part and the third part is triple the second part. which of the following equations could be used to solve the problem? 846 = x + 2x + 3x 846 = x + 2x + 6x 846 ÷ 3 = x + 2x + 6x 846 ÷ 3 = x + 2x + 3x

The 3 numbers are x,y, and z

x+y+z=846

x is the first, y is 2nd, z is the 3rd

the 2nd is twice the first means
y=2x

the third is triple the 2nd means
z=2y

alright, subsitution

x+y+z=846
subsitute 2x for y and 3y for z

x+2x+3y=846
subsitute 2x for y
x+2x+3(2x)=846
x+2x+6x=846

or
846=x+2x+6x

the answer is the 2nd option

The answer is: y would equal 3 because if you simplify the equation then it would be y= 3x+9 and if you divide 3x and 9 by 3 it would equal 3. y= 3