Find the equation of the linear function which passes through the points (-1, 3) and (4, -2). give your answer in y = mx + b form.

Hello : let  A(-1,3)    B(4,-2)
the slope is :   (YB - YA)/(XB -XA)
(-2-3)/(4+1)  = -1
an equation is : y=ax+b     a is a slope

y = -x +b

the line through point  B(4,-2) :  -2 = -1(4)+b
b = 2 
the equation is : y =-x+2

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

idk

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