How can the angle-angle similarity postulate be used to prove the two triangles are similar? explain your answer using complete sentences, and provide evidence to support your claims.

Step-by-step explanation:

Given :

In triangle ABC, ∠A = 32°,

∠B = 49°

In triangle A'B'C',

∠B' = 49°

∠C' = 99°

To prove : ΔABC and ΔA'B'C' are similar.

Proof :

In triangle ABC,

∠A = 32° and ∠B = 49°

Then ∠C = 180° - (∠A + ∠B)

= 180° - (32° + 49°)

=  180° - 81°

= 99°

Similarly, in ΔA'B'C'

∠B' = 49°  and ∠C' = 99°

Then ∠A' = 180° - (99° + 49°)

= 180° - 148°

= 32°

Now we find ∠A ≅ ∠A' ≅ 32°

∠B ≅ ∠B' ≅ 49°

and ∠C ≅ ∠C' ≅ 99°

Therefor, by both the triangles ABC and A'B'C' will be similar.

y + 11 = (1/4)(x + 16)

step-by-step explanation:

if you need just tell me and i will come to the rescue.

step-by-step explanation: