Which is a point on the circle whose center is (0, 0) and whose radius is 5?

Circle equation is given in the form of (x-a)²+(y-b)² = r²

Where (a, b) is the centre and 'r' is the radius

We have a circle with centre (0, 0) and radius of 5.

Substituting these value into the equation form, we have

(x-0)²+(y-0)² = 5²
x² + y² = 25

Hence, the equation of the circle is x² + y² = 25

It equals 1373.5 that’s the solution