Sketch the region in the plane bounded by the x-axis, the line x=2 and the curve y=(1/9)x^5. find the area of this area of this region.

Check the picture below... so the function looks like so.

now, bear in mind, the function x = 2, is just a vertical line, so we couldn't use the [ceiling] - [floor] type of function arrangement, thus let's use [right] - [left].

as you can see from the graph, which one is on the left side, and thus the left-function and which is on the right, or the right-function.

so, we have to have both in "y" terms, and the bound points are coming from the y-axis.   From the graph, we can tell the lower-bound is 0, what's the upper-bound?  let's check by seeing where those functions meet.



so, let's use that then.

No i refuse to tell you the answer but the estimate is 10