Find the center of a circle with the equation: x2+y2−2y−8x−19=0

The equation of a circle in Center-Radius form is given by :

, where the center of the circle is the point (a, b) and the radius is R.

To find the center and radius of x2+y2−2y−8x−19=0 we write this equation again in Center-Radius form by completing the square:













Thus, the center of the radius is (4, 1) and radius is 6

(4,1)