Afish tank is three-quarters (3/4) full. two-thirds (2/3) of the water leaks out, leaving 10 gallons of water in the tank. what is the capacity of the fish tank?

To solve this problem, all we have to do is to thoroughly analyze the situation step by step.

First let us work on the remaining 10 gallons of water in the tank. We are given that 2 / 3 of the water initially in the tank leaked out. Therefore this means that we are left with 1 / 3 the original amount of water which is 10 gallons, hence:

(1 / 3) Vi = 10 gallons

where Vi is the initial volume of water inside the tank, calculating for Vi:

Vi = 3 (10 gallons)

Vi = 30 gallons

We are also given that this initial volume of water is just 3 / 4 of the total capacity of the tank, therefore:

(3 / 4) Vc = Vi

where Vc is the volume capacity of the tank, calculating for Vc:

Vc = 4 Vi / 3

Vc = 4 (30 gallons) / 3

Vc = 40 gallons

Capacity of the fish tank is 40 gallons

its kind of blurry. can you put a clearer pic?

step-by-step explanation: