An ant looks up to the top of a tree with an angle of elevation of 38. if the ant is 43 feet from the base of the tree, what is the height of the tree, to the nearest tenth?
a. 33.6 feet
b. 34.1 feet
c. 35.4 feet
d. 38.5 feet

33.6 feet

Step-by-step explanation:

Given : An ant looks up to the top of a tree with an angle of elevation of 38.

To Find:  If the ant is 43 feet from the base of the tree, what is the height of the tree, to the nearest tenth?

Solution:

Refer the attached figure

An ant looks up to the top of a tree with an angle of elevation of 38.i.e.∠ACB= 38°

The ant is 43 feet from the base of the tree i.e.BC = 43 feet.

Now we are supposed to find the height of the tree i.e. AB

Now we will use trigonometric ratio

Hence the height of the tree is 33.6 feet.

20

step-by-step explanation:

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.