Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y − 15 = 0 (x + 2)2 + (y + 3)2 = 18 5x2 + 5y2 − 10x + 20y − 30 = 0 (x + 1)2 + (y − 6)2 = 46 2x2 + 2y2 − 24x − 16y − 8 = 0 x2 + y2 + 2x − 12y − 9 = 0

The equation form of a circle is (x - a)² + (y - b)² = r²

Equation 1:

x² - 4x + y² + 12y - 20 = 0 ⇒ use the completing the square method for x² - 4x and y² + 12y

x² - 4x = (x - 2)² - 4
y² + 12y = (y + 6)² - 36

Put them back together, we have
(x - 2)² - 4 + (y + 6)² - 36 - 20 = 0
(x - 2)² + (y + 6)² -4 - 36 - 20 = 0
(x - 2)² + (y + 6)² - 60 = 0
(x - 2)² + (y + 6)² = 60

Equation 2:

x² + y² + 6x - 8y - 10 = 0
(x² + 6x) + (y² - 8y) -10 = 0
(x + 3)² - 9 + (y - 4)² -16 - 10 = 0
(x + 3)² + (y - 4)² - 9 - 16 - 10 = 0
(x + 3)² + (y - 4)² - 35 = 0
(x + 3)² + (y - 4)² = 35

Equation 3:

3x² + 12x + 3y² +18y - 15 = 0
3 [x² + 4x + y² + 6y - 5] = 0
x² + 4x + y² + 6y - 5 = 0
(x² + 4x) + (y² + 6y) - 5 = 0
(x + 2)² - 4 + (y + 3)² - 9 - 5 = 0
(x + 2)² + (y + 3)² - 4 - 9 -5 = 0
(x + 2)² + (y + 3)² - 18 = 0
(x + 2)² + (y + 3)² = 18

Equation 4:

5x² + 5y² - 10x + 20y - 30 = 0
5 [x² + y² - 2x + 4y - 6] = 0
x² + y² - 2x + 4y - 6 = 0
(x² - 2x) + (y² + 4y) - 6 = 0
(x - 1)² - 2 + (y + 2)² - 4 - 6 =0
(x - 1)² + (y + 2)² - 2 - 4 - 6 = 0
(x - 1)² + (y + 2)² - 12 = 0
(x - 1)² + (y + 2)² = 12

Equation 5:

2x² + 2y² - 24x - 16y -8 = 0
2 [x² + y² - 12x - 8y - 4] = 0
x² + y² - 12x - 8y - 4 = 0
(x² - 12x) + (y² - 8y) - 4 = 0
(x - 6)² - 36 + (y - 4)² - 16 - 4 = 0
(x - 6)² + (y - 4)² -36 - 16 - 4 = 0
(x - 6)² + (y - 4)² - 56 = 0
(x - 6)² + (y - 4)² = 56

Equation 6:

x² + y² + 2x - 12y - 9 = 0
(x² + 2x) + (y² - 12y) - 9 = 0
(x + 1)² - 1 + (y - 6)² - 36 - 9 = 0
(x + 1)² + (y - 6)² - 1 - 36 - 9 = 0
(x + 1)² + (y - 6)² - 46 = 0
(x + 1)² + (y - 6)² = 46

2xy/9 is the answer to this problem