The probability that a student owns a car is 0.65, and the probability that a student owns a computer is 0.82. if he probability that a student owns both is 0.55, what is the probability that a given student owns neither a car nor a computer?

If we draw a Venn diagram, we can see that the 0.55 is the intersection of probability owning a car and probability owning a computer. To solve for the probability that the student owns neither, we need to solve first for other variables.

The probability that a student owns a car but not a computer is:

P (owns a car but not computer) = 0.65 – 0.55 = 0.10

The probability that a student owns a computer but not a car is:

P (owns a car but not computer) = 0.82 – 0.55 = 0.27

Therefore the probability of owning neither is:

P (own neither) = 1 – 0.10 – 0.27 – 0.55

P (own neither) = 0.08

Therefore there is a 8% probability that the student owns neither a car or a computer.

the highest percentage for deaths in construction from highest to lowest is as follows: falls, struck by objects, electrocution, and caught-in/between. these four are collectively known as fatal four.

in the case of falls, the type that is responsible for the overall highest death in the category is falls from roofs.

i think the amount would be $140.62