Acongested computer network has a 0.010 probability of losing a data packet and packet losses are independent events. a lost packet must be resent. round your answers to four decimal places (e. g. 98.7654). (a) what is the probability that an e-mail message with 100 packets will need any resent?

The probability of losing a data packet is 0.010.
Therefore the probability of successfully sending a data packet (not losing a data packet) is
p = 1 - 0.010 = 0.99

In 100 packet transmissions (independent events), the probability of success is
0.99¹⁰⁰ = 0.3660

The probability of losing a data packet is
1 - 0.366 = 0.6340

The probability of resending a data packet is 0.6340

3x+9+4x+x=8x+9that's the answer for your question.