What is the equation of the quadratic graph with a focus of (8, −8) and a directrix of y = −6?

f(x) = −one fourth (x − 7)2 + 1

f(x) = −one fourth (x − 8)2

f(x) = −one fourth (x − 8)2 − 7

f(x) = one fourth (x − 7)2

i think its the third one but im not sure

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.