In a small town named danville, the population today is 6125. for the last six years the population has grown by 10% every year. if the growth stay the same, what is the expected population in danville 9 years from today?
answers:
14442
14470
14397
14421

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

so, converting firstly the mixed fractions to improper fractions and then "adding".