Write an equation of a line that is perpendicular to the given line and that passes through the given point.
-x + 5y= 14; (-5, -2)

a. y=-5x-27
b. y=-1/5x-27
c. y=-1/5x-15
d. y=5x-27

To determine the equation that would be perpendicular with a certain line, we must first know the characteristics of a perpendicular line. This line would have a 90 degrees angle with another line so that the slope of this line would be the negative reciprocal of the slope of the other line. To write the equation, given a certain point we use the point-slope form of a line, y -y1 = m(x - x1).

Original line: -x + 5y= 14
                              y = x/5 + 14/5
                       slope = 1/5

Perpendicular line's slope = -5
                         y - y1 = m (x - x1)
                         y - (-2) = -5 (x - (-5))
                                  y = -5x - 25 -2
                                  y = -5x -27

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