Agame is biased such that the choices a-j have the following probabilities of winning: a 5% b 10% c 15% d 5% e 5% f 25% g 10% h 10% i 10% j 5% if you chose the letters d and h for 20 turns, how many times are you most likely to win? 1 2 3 4 5

Since we have chosen 2 letters, then the total probability of winning the game is the sum of the probabilities of each letter. Therefore:

Total probability of winning = Probability of D + Probability of H

Total probability of winning = 5% + 10%

Total probability of winning = 15%

Since we are playing the game for 20 turns, therefore out of those 20 games, we will win 15% of the time. So:   

15% = 0.15

Winning times = 0.15 * 20

Winning times = 3

Therefore we have a chance or probability to win at least 3 games out of 20 turns.

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step-by-step explanation:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.