Arectangle is placed around a semicircle as shown below. the width of the rectangle is 6ft . find the area of the shaded region. use the value 3.14 for π , and do not round your answer. be sure to include the correct unit in your answer.

As the figure is missing, I will do the most logical assumptions and explain the way to solve the problem.

Assumptions:

1) radius of the semicircle = width of the rectangle = 6ft

2) length of the rectangle = 2*radius of the semicircle = 12 ft

3) Area of the shaded region = area of the rectangle - area of the semicircle

Solution

area of the rectangle = width * length = 6 ft * 12 ft = 72 ft^2

area of the semicircle = [1/2]*π*(r^2) = [1/2]*3.14*(6ft)^2 = 56.52 ft^2

area of the shaded region = 72 ft^2 - 56.52 ft^2 = 15.48ft^2

15.48 ft^2

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