Mathematics, 05.10.2019 16:30 cats0srule
Let $s$ be the set of points with polar coordinates $(r,\theta)$ such that $ 2 \le r \le 6$ and $\frac{\pi}{3} \le \theta \le \frac{5 \pi}{6} $. find the area of $s$.
Answers: 1
![A=\int _{ \frac{ \pi }{3}} ^{ \frac{5 \pi }{6} } \,d\theta \int_{2}^{6} \,rdr \\ A= [ \frac{5 \pi }{6}- \frac{ \pi }{3}]*[ \frac{6^{2}}{2} - \frac{2^{2}}{2}] = 8 \pi](/tpl/images/0290/1725/9cba5.png)
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Let $s$ be the set of points with polar coordinates $(r,\theta)$ such that $ 2 \le r \le 6$ and $\fr...
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