Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x2 + y2 + 4x – 2y + 2 = 0 x2 + y² – 4x + 2y – 4 = 0 x2 + y² – 4x + 2y + 2 = 0

For the first picture, the center is (-2,1) and the radius is 3.
For the second picture, the center is (-2,1) and the radius is square root of 3.
For the third picture, the center is (2,-1) and the radius  is 3.
For the last picture, the center is (2,-1) and the radius is square root of 3.