Ashipment of racquetballs with a mean diameter of 60 mm and a standard deviation of 0.9 mm is normally distributed. by how many standard deviations does a ball bearing with a diameter of 58.2 mm differ from the mean?

By 2 standard deviations a ball does bearing with a diameter of 58.2 mm differ from the mean.

Step-by-step explanation:

It is given that a shipment of racquetballs with a mean diameter of 60 mm and a standard deviation of 0.9 mm is normally distributed.

Absolute difference written diameter of 58.2 mm and average diameter is

Divide the difference by standard deviation (i.e.,0.9), to find the by how many standard deviations does a ball bearing with a diameter of 58.2 mm differ from the mean.

Therefore 2 standard deviations a ball does bearing with a diameter of 58.2 mm differ from the mean.

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step-by-step explanation:

sorry no step by step

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: