Arocket is launched into the air. the projectile motion of the rocket can be modeled using h(t) = 112t –16t2, where t is the time since launch in seconds and h(t) is the height of the rocket at time t. when will the rocket be 196 feet in the air?

a.) after 2.0 seconds

b.) after 3.5 seconds

c.) after 4.5 seconds

d.) after 7.0 seconds

*the answer is b, after 3.5 seconds. if anyone wants to properly explain how this is the correct answer, i will give you brainliest.*

.

h ( t ) = 112 t - 16 t²
When the rocket is 196 feet in the air:
196 = 112 t - 16 t²
16 t² - 112 t + 196 = 0

divide everything by 4 ( just makes numbers smaller and easier to work with)

4 t² - 28 t + 49 = 0

Now factor the equation:
( 2 t - 7 )² = 0
2 t - 7 = 0
2 t = 7
t = 7 : 2
t = 3.5 s

The rocket will be 196 feet in the air after 3.5 seconds.

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk