Is 4 times as old as his . together their ages are 35. how old is jamie?

We assume that jamie is a boy or whatever

his sibbling is sibbling x

together, ages are 35

either jamie is 4 times sibbling x or sibbling x is 4 times jamie

anyway

lets say jamie=y and sibbling x=x

if we solve for jamie is 4 times as old as x then we can switch them if we are wrong

jamie is 4 times sibbling x age
x=4y
together it is 35
x+y=35

sub 4y for x

4y+y=35
5y=35
divide both sides by 5
y=7

sub back
x=4y
x=4(7)
x=28

either it is
jamie is 28 and sibbling is 7 or
sibbling is 28 and jamie is 7

depends but you didn't say who is older and who is 4 times of who

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