Information about movie ticket sales was printed in a movie magazine. in a sample of of fifty pg-rated movies, 36% had ticket sales in excess of $30,000,000. in a sample of thirty-five r-rated movies, 23% grossed over $30,000,000. suppose that this data is used to test the claim that the proportion of movies with ticket sales in excess of $30,000,000 is the same for pg movies as it is for r-rated movies. what would be the test statistic for this test? z = 1.29 z = 2.07 z = 4.005 z = 2.58

Let us say that the samples for fifty movies is 1 and samples for thirty five is 2. To solve the test statistic z, we can use the formula:

z = (p1 – p2) / sqrt [p (1 – p) (1 / n1 + 1 / n2)]

Where,

p1 = is the proportion for sample 1 = 0.36

p2 = is the proportion for sample 2 = 0.23

n1 = number of samples = 50

n2 = number of samples = 35

while p can be calculated using the formula:

p = [p1 * n1 / (n1 + n2)] + [p2 * n2 / (n1 + n2)]

p = [0.36 * 50 / (50 + 35)] + [0.23 * 35 / (50 + 35)]

p = 0.211764705 + 0.094705882

p = 0.306470587

Going back for the calculation of z:

z = (0.36 – 0.23) / sqrt [0.306 (1 – 0.306) (1 / 50 + 1 / 35)]

z = 1.279

Therefore the nearest answer is:

z = 1.29

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.