Parents sold 275 tickets for a fundraiser at the community center. student tickets cost $3, and adult tickets cost $5. the total value of tickets sold is $1,025. which system of equations represents the problem?
1. 3x + y = 275
x + 5y = 1025

2. y = 275

3x + y = 1025
x + y = 275

3. 3x + 5y = 1025
y = x + 275

x + y = 1025

Answer:

hence, the system of equations is:

                x+y=275

and         3x+5y=1025

step-by-step explanation:

let 'x' denote the number of student ticket sold.

and y denote the number of adult tickets sold.

now, it is given that:

parents sold 275 tickets for a fundraiser at the community center.

i.e. x+y=275.

also,

student tickets cost $3, and adult tickets cost $5.

the total value of tickets sold is $1,025.

hence, we have second equation as:

3x+5y=1025.

hence, the system of equations is:

                x+y=275

and         3x+5y=1025

3x + 5y = 1025
x + y = 275

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12