Abed says he has written a system of two linear equations that has an infinite number of solutions. one of the equations of the system is y = 3x – 1. which could be the other equation? y = 3x + 2 3x – y = 2 3x – y = 1 3x + y = 1

3rd Option is correct.

Step-by-step explanation:

Given: Equation is y = 3x - 1

We need to find another equation such that system of equation has infinitely solutions.

We know that System of Equations having infinitely many solution has ratio as following,

where a is coefficient of x and b is coefficient of y while c is constant term.

Clearly from Given Options Second equation is not a line with different coefficients. Its actually same with some changes.

Consider,

y = 3x - 1

transpose 3x to LHS

y - 3x = -1

Multiply both sides with -1

-y + 3x = 1

3x - y = 1

Therefore, 3rd Option is correct.

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest

answer: 1+1

step-by-step explanation: 1+1 is at least 2