Find total area of a regular pyramid with base of 2 and altitude of 3

You are not giving much information so the assumption is the base is 2 = meters and the height is 3 meters.
Find total area of a regular pyramid with base of 2 and altitude of 3

Surface Area = 16.64911 m²

I'll have to make some assumptions here.  First, I'll assume that the length of one side of the base is 2 and that the altitude (height) is 3.  

The area of the (square) base is 2^2=4.  The area of ONE triangular side is 
A=(1/2) b h; here that comes out to A = (1/2) (2) (3) = 3 square units.

The total area of the four sides is thus Atotal = 4(3 square units), or 12 square units.  Add this to the area of the base (4) to obtain the total area of the prism:  12+4=16 square units.