Describe how the graph of y=|x| – 4 is like the graph of y= |x| – 4 and how it is different.

If we were to subsitute the points and graph the equation we would notice that the shape is the same for both: a 45 degree angle line that goes upleft and up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the graph of y=|x|-4 is the same except that the graph is shifter 4 units to the right ie. the point ofo the graph/rightangle is on point (4,0)

Answer might be d.i think