Find three consecutive positive integers such that the product of the first andâ third, minus theâ second, is 1 more than 33 times the third.

 consecutive positive integers...x, x + 1, x + 2

x (x + 2) - (x + 1) = 33(x + 2) + 1
x^2 + 2x - x - 1 = 33x + 66 + 1
x^2 + x - 1 = 33x + 67
x^2 -32x - 68 = 0
(x + 2)(x - 34) = 0

x + 2 = 0
x = -2 ...not this one because it is negative

x - 34 = 0
x = 34

x + 1 = 34 + 1 = 35
x + 2 = 34 + 2 = 36

ur numbers are 34,35,36