Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. the average basketball player is 79 inches tall. approximately what percent of the adult male population is taller than the average basketball player? 0.135% 0.875% 49.875% 99.875%

A. 0.135%

Step-by-step explanation:

We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.  

We need to find the area of normal curve above the raw score 79.

First of all let us find the z-score corresponding to our given raw score.

, where,

,

,

,

.

Upon substituting our given values in z-score formula we will get,

Now we will find the P(z>3) using formula:

Using normal distribution table we will get,

Let us convert our answer into percentage by multiplying 0.00135 by 100.

Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98