X(exponent 2)+7x+6 quadratic formula

Next time, use the carrot for exponent like this:

x^2+7x+6=0

The first term is a , the second is b and the last is C

Quadratic is ax^2+bx+c=0

The formula is -(b) +- squareroot(b^2 -4(a)(c)) all over two a

So youve got:

-7 +- square root (49-4(1)(6)) divided by 2(1)
Simplify
-7 +- squareroot(49-24) / 2

-7 +- square root (25) / 2
25 is a perfect square of five, so tou have

(-7 + 5)/2 And (-7-5)/2

You answers should be : -1 & -6

X² + 7x + 6 = 0
x = -(7) +/- √((7)² - 4(1)(6))
                     2(1)
x = -7 +/- √(49 - 24)
                  2
x = -7 +/- √(25)
               2
x = -7 +/- 5
            2
x = -7 + 5      x = -7 - 5
          2                   2
x = 2              x = -12
      2                      2
x = 1              x = -6

The solution is equal to {1, -6}.

Ithink it’s b because it say 3 plastic rings and all the balls