The length of a screw produced by a machine is normally distributed with a mean of 0.65 inches and a standard deviation of 0.01 inches. what percent of screws are between 0.61 and 0.69 inches?


a. 65%
b. 68%
c. 99.7%
d. 99.9936%

D. 99.9936%.

Step-by-step explanation:

We have been given that the length of a screw produced by a machine is normally distributed with a mean of 0.65 inches and a standard deviation of 0.01 inches.

To find the percent of screws that are between 0.61 and 0.69 inches, first of we will find z-score for our given raw scores using z-score formula.

, where,

,

,

,

.

Now let us find z-score corresponding to our given raw scores.

Now let us find z-score for raw score 0.69.

Now we will use formula to find the probability between two z-score as:

Upon substituting our given values in above formula we will get,

Using normal distribution table we will get,

Now let us convert our answer into percent by multiplying 0.99994 by 100.

Therefore, 99.994% of screws are between 0.61 and 0.69 inches and option D is the correct choice.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent